In the formula stating dependence of velocity "v" on time "t", v(t) = mg/b*(1-e^-bt/m), m is the mass of the trash,g is acceleration due to gravity, b is a constant proportional to the radius of the trash and the air viscosity(both will be considered constant), and e is the base of the natural logarithm, greater than 1. Consider the behavior of speed at different times: when time "t" is equal to zero, then mg/b will be multiplied by 1-e^0, which is one minus one which is zero.
Therefore, at the drop time, velocity will be zero, which is consistent with my experiment. When time becomes very large, mg/b will be multiplied by one minus the reciprocal of e to the power of a large number, with 0 as its limit. Therefore the multiplicand in the parentheses will be one, and therefore the velocity will be constant, and equal to mg/b. Since it is constant at large t, it is terminal velocity. This is also consistent.
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